The goal of this post is to work through the following theorem:

The manifold of 1-jets of functions f: S^{n-1} \rightarrow \mathbb{R} (with its natural contact structure) is contact diffeomorphic to ST^{*} \mathbb{R}^n \cong \mathbb{R}^n \times S^{n-1}, the manifold of co-oriented contact elements in \mathbb{R}^n.

Recall: the natural contact structure of the space of 1-jets J^1(\mathbb{R}^n, \mathbb{R}) is given by dy = pdx, where p_i = \frac{\partial y}{\partial x_i}.

A point in J^1(S^{n-1}, \mathbb{R}), the space of 1-jets of f: S^{n-1} \mathbb{R}, is given by:

(q, z = f(q), p = df|_q), where q \in S^{n-1}.

Since df_q is the gradient of f at q, it means that df_q gives us the direction of fastest ascent. This direction lives in the tangent space of S^{n-1} at q. This tangent space is the space orthogonal to q, i.e. \{ q^{\perp} \}. Hence, df|_q \in \mathbb{R}^n.

It follows from the structure given in J^1(\mathbb{R}^n, \mathbb{R}) that the natural contact structure in J^1(S^{n-1}, \mathbb{R}) is given by:

dq = p dz.

What is the tautological contact structure on ST^{*} \mathbb{R}^n?

We denote a point in ST^{*} \mathbb{R}^n \cong \mathbb{R}^n \times S^{n-1} to be (Q, P), where Q \in \mathbb{R}^n and P \in S^{n-1}.

The tautological contact structure is the field of hyperplanes in ST^{*} such that the projection of each hyperplane to \mathbb{R}^n gives us a co-oriented contact element; in this case, it would be (Q, \mathcal{H}_P) (Q \in \mathbb{R}^n and \mathcal{H}_P is a co-oriented hyperplane in \mathbb{R}^n centered at Q). \mathcal{H}_P corresponds uniquely to an oriented 1-form dP, which identifies uniquely with a ray emanating from the origin, P \in S^{n-1}. We can think of P as one of the two rays in the space orthogonal to \mathcal{H}_P.

Thus, we can see that each co-oriented contact element, (Q, \mathcal{H}_P) corresponds to unique a point (Q, P) \in \mathbb{R}^n \times S^{n-1} \cong ST^{*} \mathbb{R}^n.

Since \mathcal{H}_P can be thought of as the space of vectors orthogonal to P emanating from Q, it follows that:

\mathcal{H}_P = \{ dQ \in T_Q \mathbb{R}^n : dQ \cdot P = 0 \}

The corresponding hyperplane in the tautological contact structure is the pre-image of this space in ST^{*} \mathbb{R}^n under the natural projection \pi: ST^{*} \cong \mathbb{R}^n \times S^{n-1} \rightarrow \mathbb{R}^n. This hyperplane is the set of vectors, (dQ, dP) emanating from (Q, P) such that dQ \cdot P = 0, i.e.

\pi^{-1} (\mathcal{H}_P) = \{ (dQ, dP) \in T(ST^{*} \mathbb{R}^n) : dQ \cdot P = 0 \} := \tilde{\mathcal{H}}_P

Hence, the tautological contact structure in ST^{*} \mathbb{R}^n is given by dQ \cdot P = 0.

Claim:

\Psi: J^1(S^{n-1}, \mathbb{R}) \rightarrow ST^{*} \mathbb{R}^n given by

\Psi: (q, z, p) \mapsto (qz + p, q)

is a contact diffeomorphism.

Proof:

Since q \in S^{n-1}, z \in \mathbb{R}, and p \in \{ q^{\perp} \} \cong \mathbb{R}^{n-1}, the map is well-defined and that \{qz + p: z \in \mathbb{R}, p \in \{ q^{\perp} \} \cong \mathbb{R}^n. Hence, \Psi is bijective. It is easy to see that \Psi is smooth. Hence, it is a diffeomorphism.

We now show that \Psi maps the natural contact structure in J^1 into the tautological contact structure ST^{*}.

It suffices to show that given (dp, dz, dq) at (p, z, q), the corresponding (dQ, dP) at (Q, P) (i.e. the image of d\Psi(dp, dz, dq)) satisfies P \cdot dQ = 0.

Recall, Q = qz + p and P = q.

Thus, dQ = d(qz + p) = zdq + qdz + dp, and so,

P \cdot dQ = q \cdot (zdq + qdz + dp)

= z q \cdot dq + q \cdot q dz + q \cdot dp (*)

Since dq \in T_q S^{n-1} = \{ q^{\perp} \}, it follows that q \cdot dq = 0. We also know that q \cdot q = 0. Hence,

(*) = dz + q \cdot dp.

Since q \cdot p = 0, it follows that q \cdot dp + p \cdot dq = d(q \cdot p) = 0, and so, q \cdot dp = - p \cdot q. The above gives us,

dz - p \cdot q = 0. \square

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