This post is based upon my reading on the section on exterior forms in Arnold’s Mathematical Methods of Classical Mechanics.

Let \mathbb{R}^n be an n-dim. vector space. We do not fix any special euclidean structure on \mathbb{R}^n.

Definition of 1-form: It is a linear function \omega : \mathbb{R}^n \rightarrow \mathbb{R}, i.e.

\omega(\lambda_1 \xi_1 + \lambda_2 \xi_2) = \lambda_1 \omega(\xi_1) + \lambda_2 \omega(\xi_2).

(where \lambda_1, \lambda_2 \in \mathbb{R}, \xi_1, \xi_2 \in \mathbb{R}^n).

The set of all 1-forms from \mathbb{R}^n \rightarrow \mathbb{R} is a vector space, i.e.

(\omega_1 + \omega_2)(\xi) = \omega_1(\xi) + \omega_2(\xi)

(\lambda \omega)(\xi) = \lambda \omega(\xi)

(where \lambda \in \mathbb{R}, \xi \in \mathbb{R}^n).

Claim: the space of 1-forms on \mathbb{R}^n is itself n-dimensional. It is called the dual space (\mathbb{R}^n)^{*}.

Given x_1, ..., x_n orthogonal coordinates in \mathbb{R}^n, each coordinate x_i is a 1-form, i.e.

\omega_i : (x_1, ..., x_n) \mapsto x_i

Geometrically, this is the projection of the vector onto the x_i-axis, parallel in the other directions!

Given this basis of \omega_i‘s, every 1-form can be expressed as:

\omega = a_1 x_1 + ... + a_n x_n

The value of \omega on a vector \xi is:

\omega(\xi) = a_1 x_1(\xi) + ... + a_n x_n(\xi)

where x_i(\xi) is the component of \xi in the direction of x_i.

Physical interpretation: let \xi be the displacement vector and (a_1, ..., a_n) be a uniform force field, \mathcal{A}A, in \mathbb{R}^n, then \omega(\xi) is the work that \mathcal{A} does on the displacement \xi.

Geometric interpretation: \omega(\xi) is the length of the projection of the vector \xi onto the subspace spanned by \mathcal{A} = (a_1, ..., a_n) (this projection is parallel along the other directions \hat{N}_1, ... \hat{N}_{n-1}, where \hat{N}_{\mathcal{A}} := \frac{\mathcal{A}}{|\mathcal{A}|}, \hat{N}_1, ..., \hat{N}_{n-1} form an orthonormal basis in \mathbb{R}^n).

Definition of 2-form: It is a bilinear and skew symmetric map \omega^2 : \mathbb{R}^n \times \mathbb{R}^n \rightarrow \mathbb{R}, i.e.

\omega^2(\lambda_1 \xi_1 + \lambda_2 \xi_2, \xi_3) = \lambda_1 \omega^2(\xi_1, \xi_3) + \lambda_2 \omega^2(\xi_2, \xi_3)

\omega^2(\xi_1, \xi_2) = - \omega^2(\xi_2, \xi_1)

(where \lambda_1, \lambda_2 \in \mathbb{R}, \xi_1, \xi_2, \xi_3 \in \mathbb{R}^n)

Examples of 2-forms:

Example 1: Oriented area of parallelogram S(\xi_1, \xi_2) in \mathbb{R}^n.

Example 2: Oriented area of the projection of the parallelogram on the x_1, x_2 plane in \mathbb{R}^3 (given the coordinates of \mathbb{R^3} are x_1, x_2, x_3)

    Figure taken from Arnold’s Mathematical Methods of Classical Mechanics.

    Note: this is the 2-dimensional version of the projection we saw earlier. It is not difficult to see that the oriented area of the projection of parallelograms onto any plane in \mathbb{R}^3 (or in fact \mathbb{R}^n) gives us a 2-form, i.e., we can view the 2-forms as the oriented area of projections of 2-dimensional parallelograms onto a 2-dimensional subspace of \mathbb{R}^n (with some choice of unit area)!

    Example 3: in 3-dimensional oriented Euclidean space (the orientation gives us the skew-symmetry), the flux of the fluid (described by a constant field, say \vec{v}) over the area of the parallelogram \xi_1, \xi_2 given by:

    \omega^2(xi_1, xi_2) = (\vec{v}, \xi_1, \xi_2)

    where (\vec{v}, \xi_1, \xi_2) = \vec{v} \cdot \hat{n} S(\xi_1, \xi_2) (\hat{x} is the unit vector normal to the parallelogram S(\xi_1, \xi_2) and obtained from the right-hand rule).

    Thinking about: can we interpret every 2 form as the flux of some sort of fluid field across the surface of a parallelogram?

    It is now easy to see what k-forms means.

    Algebraically, it is a k-linear and anti-symmetric function of k vectors:

    \omega^k: \mathbb{R}^n \times ... \times \mathbb{R}^n \rightarrow \mathbb{R}.

    Geometrically, it is the oriented volume of the projections of k-dimensional parallelepiped onto a k-dimensional subspace of \mathbb{R}^n (with some choice in the unit volume).

    Thus, an n-form in \mathbb{R}^n gives us the volume of the parallelpiped up to a choice of unit volume.

    Exterior Product of Two 1-forms

    Given two 1-forms \omega_1, \omega_2: \mathbb{R}^n \rightarrow \mathbb{R}, the exterior product of these two forms is a 2-form \omega_1 \wedge \omega_2: \mathbb{R}^n \times \mathbb{R}^n \rightarrow \mathbb{R} defined in the most natural way

    Algebraically, this is given by:

    (\xi_1, \xi_2) \mapsto \begin{vmatrix} \omega_1(\xi_1) & \omega_2(\xi_1) \\ \omega_1(\xi_2) & \omega_2(\xi_2) \end{vmatrix}

    it is easy to see using the properties of the determinant with respect to its rows that this map is bilinear and skew-symmetric.

    Interesting observation: the map (\omega_1, \omega_2) \mapsto \omega^1 \wedge \omega_2 is also bilinear and skew-symmetric because the properties of the rows also hold for the columns.

    Geometrically: \omega_1, \omega_2 is uniquely determined by vectors \zeta_1, \zeta_2 (maybe we can call them the characteristic vectors?). Recall, we can interpret a 1-form as the length of the projection of vectors onto a subspace spanned by another vector, say \vec{w}. The \zeta_1, \zeta_2 are the respective \vec{w}‘s for \omega_1, \omega_2. Notice that \zeta_1, \zeta_2 span a 2-dimensional plane. (\omega_1(\xi_1) := \zeta_1 \cdot \xi_1, \omega_2(\xi_1) := \zeta_2 \cdot \xi_1) is the vector obtained from the projection of \xi_1 onto (\zeta_1, \zeta_2)-plane, and (\omega_1(\xi_2), \omega_2(\xi_2)) is the vector obtained from the projection of \xi_2 onto (\zeta_1, \zeta_2)-plane. Thus, \omega_1 \wedge \omega_2 (\xi_1, \xi_2) gives us the oriented area of the parallelogram \xi_1, \xi_2 when projected onto the (\zeta_1, \zeta_2)-plane!

    From this, we can easily derive the algebraic expression as well as the geometric meaning behind the exterior product of k 1-forms.

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